capacitive isolation

[Alex555]

I ran some simulations and at only 1 khz with a 5 amp load and my monster cap I found no notable ripple. I will probably switch it just above audible frequency. I have one problem though, The resistor I use to limit the current to charge the capacitor forms a voltage divider with the load resistance, making tha capacitor not able to charge past 10v with a 15v input. Also, is it a bad idea to draw 10A surges from a bunch of AA batteris in series?

[Alex555]

Situation averted. If I do not let the charge voltage-capacitor voltage exceed .125 volts, the cap's resistance would limit the current to ten amps or so. I will just need a relay to charge it through a resistor in the first place, And I'll add some overcurrent circuitry for safety.

[Bertho]

I ran some simulations and at only 1 khz with a 5 amp load and my monster cap I found no notable ripple. I will probably switch it just above audible frequency.

At 1kHz 50% duty, 5A output current and 33mF output capacitance, you will have a ripple of Q=I*t=U*C --> U=5A*0.5ms/33mF ~0.83V.

I have one problem though, The resistor I use to limit the current to charge the capacitor forms a voltage divider with the load resistance, making tha capacitor not able to charge past 10v with a 15v input.

You can never attain the input voltage when a load is attached. The upper bound is always the input minus the ripple voltage.

Also, is it a bad idea to draw 10A surges from a bunch of AA batteris in series?

You'd probably never get that much current out of AA batteries unless you put a lot of them in parallel. The internal resistance is in the order 1-to-50Ohm and dependent on temperature, usage and age.

[Alex555]

I think I will just limit my load to two amps. I should have far less problems that way. I also calculated the load resistance of my battery pack and it will limit current to 30 amps.